y=(k+1)x^2-3x+(k+1)

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Solution for y=(k+1)x^2-3x+(k+1) equation:


Simplifying
y = (k + 1) * x2 + -3x + (k + 1)

Reorder the terms:
y = (1 + k) * x2 + -3x + (k + 1)

Reorder the terms for easier multiplication:
y = x2(1 + k) + -3x + (k + 1)
y = (1 * x2 + k * x2) + -3x + (k + 1)

Reorder the terms:
y = (kx2 + 1x2) + -3x + (k + 1)
y = (kx2 + 1x2) + -3x + (k + 1)

Reorder the terms:
y = kx2 + 1x2 + -3x + (1 + k)

Remove parenthesis around (1 + k)
y = kx2 + 1x2 + -3x + 1 + k

Reorder the terms:
y = 1 + k + kx2 + -3x + 1x2

Solving
y = 1 + k + kx2 + -3x + 1x2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 1 + k + kx2 + -3x + 1x2

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